Prepare for the Six Sigma Black Belt Exam. Access comprehensive flashcards and multiple-choice questions with detailed explanations. Enhance your skills and ensure exam success!

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

Practice this question and more.


How many unique meetings consisting of one black belt and two quality engineers can be formed from five black belts and eight quality engineers?

  1. 40

  2. 80

  3. 140

  4. 280

The correct answer is: 140

To determine how many unique meetings can be formed with one black belt and two quality engineers from five black belts and eight quality engineers, we need to utilize combinations. First, we consider the selection of one black belt. Since there are five black belts available, the number of ways to choose one black belt can be calculated using combinations. This is given by: C(5, 1) = 5 Next, we need to select two quality engineers from the eight available. The number of ways to choose two quality engineers can also be calculated using the combinations formula: C(8, 2) = 8! / (2!(8-2)!) = 8! / (2! * 6!) = (8 * 7) / (2 * 1) = 28 To find the total number of unique meetings, we multiply the number of ways to choose the black belt by the number of ways to choose the quality engineers: Total unique meetings = C(5, 1) * C(8, 2) = 5 * 28 = 140 Thus, the correct answer is 140, indicating that it's possible to create 140 distinct combinations of one black belt and two quality